Optimal. Leaf size=129 \[ -\frac {\cot ^7(e+f x) (\sec (e+f x)+1)}{7 a^3 c^4 f}+\frac {\cot ^5(e+f x) (6 \sec (e+f x)+7)}{35 a^3 c^4 f}-\frac {\cot ^3(e+f x) (24 \sec (e+f x)+35)}{105 a^3 c^4 f}+\frac {\cot (e+f x) (16 \sec (e+f x)+35)}{35 a^3 c^4 f}+\frac {x}{a^3 c^4} \]
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Rubi [A] time = 0.17, antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {3904, 3882, 8} \[ -\frac {\cot ^7(e+f x) (\sec (e+f x)+1)}{7 a^3 c^4 f}+\frac {\cot ^5(e+f x) (6 \sec (e+f x)+7)}{35 a^3 c^4 f}-\frac {\cot ^3(e+f x) (24 \sec (e+f x)+35)}{105 a^3 c^4 f}+\frac {\cot (e+f x) (16 \sec (e+f x)+35)}{35 a^3 c^4 f}+\frac {x}{a^3 c^4} \]
Antiderivative was successfully verified.
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Rule 8
Rule 3882
Rule 3904
Rubi steps
\begin {align*} \int \frac {1}{(a+a \sec (e+f x))^3 (c-c \sec (e+f x))^4} \, dx &=\frac {\int \cot ^8(e+f x) (a+a \sec (e+f x)) \, dx}{a^4 c^4}\\ &=-\frac {\cot ^7(e+f x) (1+\sec (e+f x))}{7 a^3 c^4 f}+\frac {\int \cot ^6(e+f x) (-7 a-6 a \sec (e+f x)) \, dx}{7 a^4 c^4}\\ &=-\frac {\cot ^7(e+f x) (1+\sec (e+f x))}{7 a^3 c^4 f}+\frac {\cot ^5(e+f x) (7+6 \sec (e+f x))}{35 a^3 c^4 f}+\frac {\int \cot ^4(e+f x) (35 a+24 a \sec (e+f x)) \, dx}{35 a^4 c^4}\\ &=-\frac {\cot ^7(e+f x) (1+\sec (e+f x))}{7 a^3 c^4 f}+\frac {\cot ^5(e+f x) (7+6 \sec (e+f x))}{35 a^3 c^4 f}-\frac {\cot ^3(e+f x) (35+24 \sec (e+f x))}{105 a^3 c^4 f}+\frac {\int \cot ^2(e+f x) (-105 a-48 a \sec (e+f x)) \, dx}{105 a^4 c^4}\\ &=-\frac {\cot ^7(e+f x) (1+\sec (e+f x))}{7 a^3 c^4 f}+\frac {\cot ^5(e+f x) (7+6 \sec (e+f x))}{35 a^3 c^4 f}+\frac {\cot (e+f x) (35+16 \sec (e+f x))}{35 a^3 c^4 f}-\frac {\cot ^3(e+f x) (35+24 \sec (e+f x))}{105 a^3 c^4 f}+\frac {\int 105 a \, dx}{105 a^4 c^4}\\ &=\frac {x}{a^3 c^4}-\frac {\cot ^7(e+f x) (1+\sec (e+f x))}{7 a^3 c^4 f}+\frac {\cot ^5(e+f x) (7+6 \sec (e+f x))}{35 a^3 c^4 f}+\frac {\cot (e+f x) (35+16 \sec (e+f x))}{35 a^3 c^4 f}-\frac {\cot ^3(e+f x) (35+24 \sec (e+f x))}{105 a^3 c^4 f}\\ \end {align*}
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Mathematica [B] time = 1.41, size = 362, normalized size = 2.81 \[ \frac {\csc \left (\frac {e}{2}\right ) \sec \left (\frac {e}{2}\right ) \csc ^7\left (\frac {1}{2} (e+f x)\right ) \sec ^5\left (\frac {1}{2} (e+f x)\right ) (-22860 \sin (e+f x)+5715 \sin (2 (e+f x))+11430 \sin (3 (e+f x))-4572 \sin (4 (e+f x))-2286 \sin (5 (e+f x))+1143 \sin (6 (e+f x))-26208 \sin (2 e+f x)+14080 \sin (e+2 f x)+16400 \sin (2 e+3 f x)+11760 \sin (4 e+3 f x)-7904 \sin (3 e+4 f x)-3360 \sin (5 e+4 f x)-3952 \sin (4 e+5 f x)-1680 \sin (6 e+5 f x)+2816 \sin (5 e+6 f x)-16800 f x \cos (2 e+f x)-4200 f x \cos (e+2 f x)+4200 f x \cos (3 e+2 f x)-8400 f x \cos (2 e+3 f x)+8400 f x \cos (4 e+3 f x)+3360 f x \cos (3 e+4 f x)-3360 f x \cos (5 e+4 f x)+1680 f x \cos (4 e+5 f x)-1680 f x \cos (6 e+5 f x)-840 f x \cos (5 e+6 f x)+840 f x \cos (7 e+6 f x)+3136 \sin (e)-30112 \sin (f x)+16800 f x \cos (f x))}{6881280 a^3 c^4 f} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.45, size = 232, normalized size = 1.80 \[ \frac {176 \, \cos \left (f x + e\right )^{6} - 71 \, \cos \left (f x + e\right )^{5} - 335 \, \cos \left (f x + e\right )^{4} + 125 \, \cos \left (f x + e\right )^{3} + 225 \, \cos \left (f x + e\right )^{2} + 105 \, {\left (f x \cos \left (f x + e\right )^{5} - f x \cos \left (f x + e\right )^{4} - 2 \, f x \cos \left (f x + e\right )^{3} + 2 \, f x \cos \left (f x + e\right )^{2} + f x \cos \left (f x + e\right ) - f x\right )} \sin \left (f x + e\right ) - 57 \, \cos \left (f x + e\right ) - 48}{105 \, {\left (a^{3} c^{4} f \cos \left (f x + e\right )^{5} - a^{3} c^{4} f \cos \left (f x + e\right )^{4} - 2 \, a^{3} c^{4} f \cos \left (f x + e\right )^{3} + 2 \, a^{3} c^{4} f \cos \left (f x + e\right )^{2} + a^{3} c^{4} f \cos \left (f x + e\right ) - a^{3} c^{4} f\right )} \sin \left (f x + e\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.44, size = 150, normalized size = 1.16 \[ \frac {\frac {6720 \, {\left (f x + e\right )}}{a^{3} c^{4}} + \frac {6720 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{6} - 1015 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} + 168 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 15}{a^{3} c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{7}} - \frac {7 \, {\left (3 \, a^{12} c^{16} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 40 \, a^{12} c^{16} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 435 \, a^{12} c^{16} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )\right )}}{a^{15} c^{20}}}{6720 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.98, size = 174, normalized size = 1.35 \[ -\frac {\tan ^{5}\left (\frac {e}{2}+\frac {f x}{2}\right )}{320 f \,a^{3} c^{4}}+\frac {\tan ^{3}\left (\frac {e}{2}+\frac {f x}{2}\right )}{24 f \,a^{3} c^{4}}-\frac {29 \tan \left (\frac {e}{2}+\frac {f x}{2}\right )}{64 f \,a^{3} c^{4}}-\frac {1}{448 f \,a^{3} c^{4} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{7}}+\frac {1}{40 f \,a^{3} c^{4} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{5}}-\frac {29}{192 f \,a^{3} c^{4} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{3}}+\frac {1}{f \,a^{3} c^{4} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )}+\frac {2 \arctan \left (\tan \left (\frac {e}{2}+\frac {f x}{2}\right )\right )}{f \,a^{3} c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.44, size = 187, normalized size = 1.45 \[ -\frac {\frac {7 \, {\left (\frac {435 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {40 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3} c^{4}} - \frac {13440 \, \arctan \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1}\right )}{a^{3} c^{4}} - \frac {{\left (\frac {168 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {1015 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {6720 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} - 15\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{7}}{a^{3} c^{4} \sin \left (f x + e\right )^{7}}}{6720 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.85, size = 209, normalized size = 1.62 \[ -\frac {15\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{12}+21\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{12}-280\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{10}+3045\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8-6720\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6+1015\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4-168\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{10}\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2-6720\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7\,\left (e+f\,x\right )}{6720\,a^3\,c^4\,f\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {1}{\sec ^{7}{\left (e + f x \right )} - \sec ^{6}{\left (e + f x \right )} - 3 \sec ^{5}{\left (e + f x \right )} + 3 \sec ^{4}{\left (e + f x \right )} + 3 \sec ^{3}{\left (e + f x \right )} - 3 \sec ^{2}{\left (e + f x \right )} - \sec {\left (e + f x \right )} + 1}\, dx}{a^{3} c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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